Question
‘P’ alone can paint a house in 18 days, while
‘P’ and ‘Q’ together can do it in 12 days. If ‘Q’ started the work and left after 6 days, how many days will ‘P’ take to complete the painting?Solution
ATQ,
Let the total work = 36 {L.C.M of 18 and 12}
Efficiency of ‘P’ = 36 ÷ 18 = 2 units/day
Combined efficiency of ‘P’ and ‘Q’ = 36 ÷ 12 = 3 units/day
So, efficiency of ‘Q’ alone = 3 – 2 = 1 unit/day
Work done by ‘Q’ in 6 days = 1 × 6 = 6 units
Remaining work = 36 – 6 = 30 units
Time taken by ‘P’ alone = 30 ÷ 2 = 15 days
More Time and work Questions
- A series is given with one term missing. Choose the correct alternatives from the given ones that will complete the series.
57, 59, 56, 61, 54, ___ - Which letter-cluster will replace the question mark (?) in the following series?
RGV, UME, ?, AYW, DEF - Which letter and number cluster will replace the question mark (?) to complete the given series?
LT6, KU12, IW24, FZ48, ____ - Which letter-cluster will replace the question mark (?) in the following series?
NPQR, OORQ, PNSP, ____, RLUN - Select the number from among the given options that can replace the question mark (?) in the following series.
17, 18, 22, 31, 47, ___
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