Question
A can complete a work in 12 days and B can complete the
same work in 18 days. A works alone for 4 days and then B alone finishes the remaining work. In how many days does B work?Solution
Let total work = LCM of 12 and 18 = 36 units A’s 1-day work = 36 ÷ 12 = 3 units B’s 1-day work = 36 ÷ 18 = 2 units Work done by A in 4 days = 4 × 3 = 12 units Remaining work = 36 − 12 = 24 units B’s 1-day work = 2 units So, days taken by B = 24 ÷ 2 = 12 days
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