Question
A can do a piece of work in 24 days. B can do the same
work in 16 days and C can do the same work in 5/4th time required by both A and B together. A and B work together for 6 days, then C complete the remaining work. How many day did C work?Solution
=> (A + B) together = 48/5 day => C alone = (48/5) × (5/4) days = 12 days Remaining work = 48 – 5 × 6 = 18 C’s work = (18 × 12)/48 = 9/2 days
More Time and work Questions
If (a + b + c) = 18 and (ab + bc + ca) = 100, then find the value of (a² + b² + c²).
If x + y = 4 and (1/x) + (1/y) = 24/7, then the value of (x3 + y3).
[a/(2a² + 5a + 2)] = 1/6 , then find the value of (a+1)/a ?
If ( p = 60 - q - r ) and ( pq + r(q + p) = 1080), then find the value of ( p2 + q2 + r2).
If (6x + y) = 180 and 5x:2y = 25:12, then find the value of (2x² + 5y²).
- If (x 2 = 2x – 1), then find the value of [x³ + (x⁴/1)][1 - x³]
- The ratio of M to N is 4:9, and that of N to O is 3:2. If the difference between O and M is 60, what is the total of M, N, and O?
If (3x - y) = 3, xy = (2/3), then find the value of {x3 - (y3/27)}
If 0.125x3 +0.216y3 = 210 and 0.25x2 + 0.36y2 = 10.30 then find the value of 0.5x + 0.6y.
- If (x + y + z) = 14 and (xy + yz + zx) = 50, then find the value of (x² + y² + z²).
Relevant for Exams:
