Question
A can do a piece of work in 24 days. B can do the same
work in 16 days and C can do the same work in 5/4th time required by both A and B together. A and B work together for 6 days, then C complete the remaining work. How many day did C work?Solution
=> (A + B) together = 48/5 day => C alone = (48/5) × (5/4) days = 12 days Remaining work = 48 – 5 × 6 = 18 C’s work = (18 × 12)/48 = 9/2 days
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