Question
A work can be completed by ‘A’ and ‘B’, alone in
20 days and 10 days, respectively. Find the number of days taken by ‘C’ to complete the same work alone if ‘A’, ‘B’ and ‘C’ together can complete the whole work in 5 days.Solution
Let total work = 20 units (LCM of 20 and 10) Efficiency of ‘A’ = (20/20) = 1 units/day Efficiency of ‘B’ = (20/10) = 2 units/day Combined efficiency of ‘A’, ‘B’ and ‘C’ = (20/5) = 4 units/day Efficiency of ‘C’ = 4 – (1 + 2) = 1 units/day Required time taken = (20/1) = 20 days
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
Quantity I: The price of rice is decreased by 30%, by how much % the consumption is increase so that the expenditure will decreased by 10%?
Quant...
I. 4 x ² - 4 x + 1 = 0                              Â
II. 4 y ² + 4 y  + 1 = 0
...I. 27(p + 2) = 2p(24 – p)
II. 2q2 – 25q + 78 = 0
I. 35x² + 83x + 36 = 0
II. 42y² + 53y + 15 = 0
What are the coordinates of the point which divides the line joining (-1, 7) and (4, 3) in the ratio 2:3?
I. 49y2 + 35y + 6 = 0
II. 12x2 + 17 x + 6 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 42x + 392 = 0
Equation 2: y² - 46y + 480 = 0
I. 4x2 + 25x + 36 =0
II. 2y2 + 5y + 3 = 0
I. (x13/5 ÷7) = 5488 ÷ x7/5
II. (y2/3 × y2/3 ) ÷ √4 = (343y)1/3...
