Let total work = 20 units (LCM of 20 and 10) Efficiency of ‘A’ = (20/20) = 1 units/day Efficiency of ‘B’ = (20/10) = 2 units/day Combined efficiency of ‘A’, ‘B’ and ‘C’ = (20/5) = 4 units/day Efficiency of ‘C’ = 4 – (1 + 2) = 1 units/day Required time taken = (20/1) = 20 days
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‘n’ men working 20 hours a day can complete a work in 8 days while (6n – 4) men working 10 hours a day can complete the same work in 8...
Two people, A and B, working separately can sanitize a building in 6 and 10 hours, respectively. They work in stretches of one hour alternately. If A be...
A and B working together completed a job in 40/9 days. If A had worked twice as efficiently as she did and B had worked 1/3 of his actual efficiency, th...
