Question
'A' alone can do some work in 12 days, 'B' alone can do
the same work in 24 days. If they work on alternate days, starting with 'B', then the work will be finished in:Solution
Let the total work be 24 units {LCM (12 and 24)} So, efficiency of 'A' = 24 ÷ 12 = 2 units/day And efficiency of 'B' = 24 ÷ 24 = 1 unit/day Work done in every 2 days (B + A) = 1 + 2 = 3 units So, work done in 16 days by 'B' and 'A' = (16 ÷ 2) x 3 = 24 units Total time taken = 16 days
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