Let the total work = 200 units Then, efficiency of ‘A’ = (200/50) = 4 units/hour Work completed by ‘A’ alone in 40 hours = 4 × 40 = 160 units Remaining work = 200 – 160 = 40 units So, efficiency of ‘B’ = 40/10 = 4 units/hour Therefore, combined efficiency of ‘A’ and ‘B’ = 4 + 4 = 8 units/hour So, time taken by ‘A’ and ‘B’ together to complete the work = (200/8) = 25 hours
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