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    Question

    ‘D’ alone can finish a job in 50 days, while ‘D’

    and ‘E’ together can complete it in 20 days. If ‘E’ worked alone for 22 days and then left, how many days will ‘D’ take to complete the remaining work?
    A 25 days Correct Answer Incorrect Answer
    B 40 days Correct Answer Incorrect Answer
    C 33 days Correct Answer Incorrect Answer
    D 17 days Correct Answer Incorrect Answer

    Solution

    Let the total work = 100 units {L.C.M of 50 and 20}
    Then, efficiency of ‘D’ = 100 ÷ 50 = 2 units/day
    Combined efficiency of ‘D’ and ‘E’ = 100 ÷ 20 = 5 units/day
    So, efficiency of ‘E’ = 5 – 2 = 3 units/day
    So, work done by ‘E’ alone in 22 days = 3 × 22 = 66 units
    Remaining work = 100 – 66 = 34 units
    Time taken by 'D' alone to complete the remaining work = 34 ÷ 2 = 17 days

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