Question
βDβ alone can finish a job in 50 days, while βDβ
and βEβ together can complete it in 20 days. If βEβ worked alone for 22 days and then left, how many days will βDβ take to complete the remaining work?Solution
Let the total work = 100 units {L.C.M of 50 and 20}
Then, efficiency of βDβ = 100 Γ· 50 = 2 units/day
Combined efficiency of βDβ and βEβ = 100 Γ· 20 = 5 units/day
So, efficiency of βEβ = 5 β 2 = 3 units/day
So, work done by βEβ alone in 22 days = 3 Γ 22 = 66 units
Remaining work = 100 β 66 = 34 units
Time taken by 'D' alone to complete the remaining work = 34 Γ· 2 = 17 days
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