Question
If Rs. 10,000 is invested at a simple interest rate of
8% per annum, it accrues Rs. 1,200 as interest over a period of 't' years. Given the same duration 't', what annual simple interest rate is required for an investment of Rs. 16,000 to generate Rs. 2,400 in interest?Solution
Simple interest = (principal X rate X time) Γ· 100
ATQ;
1,200 = (10,000 X 8 X t) Γ· 100
Or, 't' = (1,200/800)
Or, 't' = 1.5
Let the required rate of interest be 'R%' p.a.
So, 2,400 = 16,000 X 1.5 X R Γ· 100
Or, 240R = 2,400
Or, 'R' = 10
Therefore, required rate of interest = 10% p.a.
32 × 3 (54 – 15) + 186 ÷ 3 ÷ 2 – (21)² = ?
17% of 250 + ? = 108
32 + 26 Γ (484 Γ· 44) + 450 Γ· 9 = ?Β
40 Γ 5 + 27) Γ 9 = ?
What will come in the place of question mark (?) in the given expression?
193...
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
What will come in the place of question mark (?) in the given expression?
β1296 + (2/3 of 45% of 480) = ?
- Determine the value of βpβ if p = β529 + β1444
120% of 250 + 110 + 135 Γ· 5 = ?