Question
A can complete a work in 18 days and B can complete the same work in 24 days. They work together for 6 days, after which A leaves. In how many more days will B finish the remaining work?
Solution
ATQ, A's 1-day work = 1/18 B's 1-day work = 1/24 Together 1-day work = 1/18 + 1/24 = 4/72 + 3/72 = 7/72 Work done in 6 days = 6 x 7/72 = 42/72 = 7/12 Remaining work = 1 - 7/12 = 5/12 B alone does 1/24 work in 1 day Time taken by B = (5/12) x 24 = 10 days
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