Question
50% of the work done by Meena in 2 days is equal to 25% of
the work done by Lata in 5 days. If Meena can complete the job alone in 10 days, then how long will Lata take to complete the same task?Solution
ATQ,
Let the efficiency of Meena and Lata be 'x' units/day and 'y' units/day respectively.
So, 0.5 × x × 2 = 0.25 × y × 5
So, x = (5/2) × y
Total work = 10 × x = 10x units
Time taken by Lata to complete the work:
= (10x / y) = {10 × (5/2) y} ÷ y = 25 days
12 78 385 ? 4629 9260
...If 18 x 10 42 -22,
Then, 50% of 2x - 25% of x = ?
...22Â Â Â 23Â Â Â Â 32Â Â Â Â 57Â Â Â 106Â Â Â ?
12Â Â Â Â Â Â Â Â Â Â Â Â Â 10Â Â Â Â Â Â Â Â Â Â Â Â 13Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 18.5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 25.50Â Â Â Â Â Â Â ...
148, ‘?’ , 15 4 , 17 8 , 23 8 , 35 8 , 56 8
40 30 20 ? 7.5 4.375
Identify the logic of the below given series and given answer.
Series I :: 81, 89, 116, 241, (A), 1915
Series II :: (B), 204, 208, 4...
6 10 ? 210 1672 16710
...125 36 343 ? 729 100
...16 18 14 20 12 ?
...
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