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    Question

    'A' is capable of completing a specific task on their

    own in 20 days. 'B' can independently handle 60% of the same task in 18 days. If 'A' and 'B' collaborate on this task, how long will it take them to finish it completely?
    A 12 days Correct Answer Incorrect Answer
    B 10 days Correct Answer Incorrect Answer
    C 15 days Correct Answer Incorrect Answer
    D 18 days Correct Answer Incorrect Answer
    E 16 days Correct Answer Incorrect Answer

    Solution

    Time taken by 'A' to finish the entire work alone = 25 ÷ 1.25 = 20 days And time taken by 'B' to finish the entire work alone = 18 ÷ 0.6 = 30 days Let the total work be 60 units. {LCM (20 and 30)} So, efficiency of 'A' = 60 ÷ 20 = 3 units/day And efficiency of 'B' = 60 ÷ 30 = 2 units/day So, required time = {60/(3 + 2)} = 12 days

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