Question
'A' is capable of completing a specific task on their
own in 20 days. 'B' can independently handle 60% of the same task in 18 days. If 'A' and 'B' collaborate on this task, how long will it take them to finish it completely?Solution
Time taken by 'A' to finish the entire work alone = 25 ÷ 1.25 = 20 days And time taken by 'B' to finish the entire work alone = 18 ÷ 0.6 = 30 days Let the total work be 60 units. {LCM (20 and 30)} So, efficiency of 'A' = 60 ÷ 20 = 3 units/day And efficiency of 'B' = 60 ÷ 30 = 2 units/day So, required time = {60/(3 + 2)} = 12 days
Simplify:
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