Question
Suppose [a + (1/16a)] = 3, then the value of [16a³ +
(1/256a³)] is:Solution
ATQ,
If a + 1/16a = 3
Cubing both sides, we get;
So, a³ + 1/4096a³ + 3 × a × 1/16a × 3 = 27
Or, a³ + 1/4096a³ = 27 – 9/16 = 423/16
Multiplying both sides by 16, we get;
16a³ + 1/256a³ = 423
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