Question
(x – 6) 2 + (y + 2) 2 + (z – 4) 2 = 0, then find the value of 4x - 3y + z.
Solution
If (x – 6) 2 + (y + 2) 2 + (z – 4) 2 = 0, then (x = 6), (y = -2), and (z = 4).
So,
- x - 6 = 0 → x = 6
- y + 2 = 0 → y = -2
- z - 4 = 0 → z = 4
Therefore, required value:
4(6) - 3(-2) + 4 = 24 + 6 + 4 = 34
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