Question
(x – 6) 2 + (y + 2) 2 + (z –
4) 2 = 0, then find the value of 4x - 3y + z.Solution
If (x – 6) 2 + (y + 2) 2 + (z – 4) 2 = 0, then (x = 6), (y = -2), and (z = 4).
So,
- x - 6 = 0 → x = 6
- y + 2 = 0 → y = -2
- z - 4 = 0 → z = 4
Therefore, required value:
4(6) - 3(-2) + 4 = 24 + 6 + 4 = 34
17    18      14       ?      7       32
...7 7 28 252 ?
...94Â Â Â 115Â Â Â 138Â Â Â 163Â Â Â Â 190Â Â Â Â ?
62, 87, 137, ?, 312, 437
135, 148, ?, 184, 207, 236
8    13    36    123    ?   2585
195% of 1420 + 72 × 25 =?
70, 69, 73, 64,80, 55, ?
64, 66, 69, 74, 81, ?
What value should come in the place of (?) in the following number series?
14, 43, 132, 401, 1210, ?, 10928