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    Question

    (p + 3) 2 + (q тАУ 7) 2 + (r +

    4)2 = 0, then find the value of p + q тАУ r.
    A 8 Correct Answer Incorrect Answer
    B -8 Correct Answer Incorrect Answer
    C 16 Correct Answer Incorrect Answer
    D 4 Correct Answer Incorrect Answer

    Solution

    If (p + 3) 2 + (q тАУ 7) 2 + (r + 4)2 = 0, then (p = -3), (q = 7), and (r = -4).

    So,
    - p + 3 = 0 тЖТ p = -3
    - q - 7 = 0 тЖТ q = 7
    - r + 4 = 0 тЖТ r = -4

    Therefore, required value:
    -3 + 7 - (-4) = -3 + 7 + 4 = 8

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