Question
(p + 3) 2 + (q β 7) 2 + (r +
4)2 = 0, then find the value of p + q β r.Solution
If (p + 3) 2 + (q β 7) 2 + (r + 4)2 = 0, then (p = -3), (q = 7), and (r = -4).
So,
- p + 3 = 0 β p = -3
- q - 7 = 0 β q = 7
- r + 4 = 0 β r = -4
Therefore, required value:
-3 + 7 - (-4) = -3 + 7 + 4 = 8
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