Question
A can complete a piece of work in 16 days and B can complete it in 24 days. They work together for 4 days and then B leaves. In how many total days is the work completed?
Solution
Take total work = LCM(16, 24) = 48 units. A’s rate = 48/16 = 3 units/day B’s rate = 48/24 = 2 units/day Together (first 4 days): Daily work = 3 + 2 = 5 units Work done in 4 days = 5 × 4 = 20 units Remaining work = 48 − 20 = 28 units Now only A works: Time taken by A for remaining work = 28 / 3 days = 9⅓ days Total time = 4 + 9⅓ = 13⅓ days
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