Question
A can finish a work in 18 days and B can finish it in 24 days. They work together for 6 days, then A leaves. In how many more days will B finish the remaining work?
Solution
ATQ, Aβs rate = 1/18, Bβs rate = 1/24 Together rate = 1/18 + 1/24 = (4+3)/72 = 7/72 Work done in 6 days = 6*(7/72) = 42/72 = 7/12 Remaining work = 1 β 7/12 = 5/12 Time for B = (5/12)/(1/24) = (5/12)*24 = 10 days Answer: 10 days
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