‘A’ can complete 30% of a work in 3 days. ‘B’ takes 5 days more than ‘A’ to complete the work and ‘B’ is 33⅓% more efficient than ‘C’. ‘A’ started the work alone; on the 2nd day, he is joined by ‘B’ only; on the 3rd day, he is joined by ‘C’ only; on the 4th day, he works alone again, and so on. They worked this way for 6 days. The sum of the time taken to complete the remaining work by ‘A’ alone and by ‘B’ alone is how much percent more/less than that by ‘C’ alone?

Time taken by ‘A’ to complete the work alone: = 3 / 0.3 = 10 days Time taken by ‘B’ to complete the work alone: = 10 + 5 = 15 days Time taken by ‘C’ to complete the work alone: = 15 × (4 / 3) = 20 days Total Work (LCM of 10, 15, 20): = 60 units Efficiency of ‘A’: = 60 / 10 = 6 units/day Efficiency of ‘B’: = 60 / 15 = 4 units/day Efficiency of ‘C’: = 60 / 20 = 3 units/day Work done on Day 1 (A alone): = 6 units Work done on Day 2 (A + B): = 6 + 4 = 10 units Work done on Day 3 (A + C): = 6 + 3 = 9 units Work done in 3 days (1 cycle): = 6 + 10 + 9 = 25 units Work done in 6 days (2 cycles): = 25 × 2 = 50 units Remaining work: = 60 – 50 = 10 units Time taken by ‘A’ to complete remaining work alone: = 10 / 6 = 5/3 days (≈ 1.67 days) Time taken by ‘B’ to complete remaining work alone: = 10 / 4 = 5/2 = 2.5 days Time taken by ‘C’ to complete remaining work alone: = 10 / 3 = 10/3 days (≈ 3.33 days) Sum of time taken by ‘A’ and ‘B’ alone: = 5/3 + 5/2 = 25/6 days Required percentage: = [ (25/6 – 10/3) / (10/3) ] × 100 = [ (5/6) / (10/3) ] × 100 = 25% more