Question
A can complete a work in 20 days and B can complete it
in 30 days. They work together for 6 days, then B leaves. In how many total days will the work be completed?Solution
ATQ, Aβs 1-day work = 1/20 Bβs 1-day work = 1/30 Together 1-day work = 1/20 + 1/30 = (3+2)/60 = 5/60 = 1/12 Work done in 6 days = 6 Γ (1/12) = 1/2 Remaining work = 1/2 A alone time for remaining = (1/2) Γ· (1/20) = (1/2)Γ20 = 10 days Total time = 6 + 10 = 16 days
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