Question
A’ and ‘B’ together can complete a work in 20 days
while ‘A’ takes 30 days to complete the same work alone. If ‘C’ is 60% more efficient than ‘B’, then find the time taken by ‘C’ alone to complete the whole work.Solution
Let the total work = 60 units Efficiency of (A + B) = 60/20 = 3 units/day Efficiency of ‘A’ = 60/30 = 2 unit/day Therefore, efficiency of ‘B’ = 3 – 2 = 1 units/day Efficiency of ‘C’ = 1.6 × 1 = 1.6 units/day Required time taken = 60/1.6 = 37.5 days
18Â Â Â 19Â Â Â 34Â Â Â 111Â Â Â Â 428Â Â Â Â 2165Â Â Â Â ?
...75, 80, 95, ?, 155, 200
- What will come in place of the question mark (?) in the following series?
3, 10, 29, 66, 127, ? 9 10 36 333 ? 132825
...What value should come in the place of (?) in the following number series?
19, 235, 260, 324, 333, ?
3, 10, 29, 66, ?
43          86          258        ?             5160                     30960
...18, 34, 70, 134, ?, 378
840, 2520, 630, 3150, ?, 3675
What will come in place of the question mark (?) in the following series?
4, 2605, 5309, 8118, ?
