A’ and ‘B’ together can complete a work in 20 days while ‘A’ takes 25 days to complete the same work alone. If ‘C’ is 60% more efficient than ‘B’, then find the time taken by ‘C’ alone to complete the whole work.
Let the total work = 100 units Efficiency of (A + B) = 100/20 = 5 units/day Efficiency of ‘A’ = 100/25 = 4 unit/day Therefore, efficiency of ‘B’ = 5 – 4 = 1 units/day Efficiency of ‘C’ = 1.6 × 1 = 1.6 units/day Required time taken = 100/1.6 = 62.5 days
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