Question
Aβ and βBβ together can complete a work in 20 days
while βAβ takes 25 days to complete the same work alone. If βCβ is 60% more efficient than βBβ, then find the time taken by βCβ alone to complete the whole work.Solution
Let the total work = 100 units Efficiency of (A + B) = 100/20 = 5 units/day Efficiency of βAβ = 100/25 = 4 unit/day Therefore, efficiency of βBβ = 5 β 4 = 1 units/day Efficiency of βCβ = 1.6 Γ 1 = 1.6 units/day Required time taken = 100/1.6 = 62.5 days
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