Question
Aβ and βBβ together can complete a work in 10 days
while βAβ takes 18 days to complete the same work alone. If βCβ is 25% more efficient than βBβ, then find the time taken by βCβ alone to complete the whole work.Solution
Let the total work = 90 units Efficiency of (A + B) = 90/10 = 9 units/day Efficiency of βAβ = 90/18 = 5 unit/day Therefore, efficiency of βBβ = 9 β 5 = 4 units/day Efficiency of βCβ = 1.25 Γ 4 = 5 units/day Required time taken = 90/5 = 18 days
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