Question
I. 4x² -  15x + 9 = 0 II. 20y² -  23y + 6 =
0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 4x² -  15x + 9 = 0 4x² -  12x - 3 x + 9 = 0 4 x(x – 3) – 3 (x – 3) = 0 (4 x – 3) (x – 3) = 0 ∴ x = 3, 3/4 II. 20y² -  23y + 6 = 0 20y² -  8y - 15 y + 6 = 0 4 y(5 y – 2) – 3(5 y - 2) = 0 (4 y - 3) (5 y – 2) = 0  ∴ y = 2/5 ,3/4 Hence, x ≥ y
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