Question
I. 4x² -  15x + 9 = 0 II. 20y² -  23y + 6 =
0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 4x² -  15x + 9 = 0 4x² -  12x - 3 x + 9 = 0 4 x(x – 3) – 3 (x – 3) = 0 (4 x – 3) (x – 3) = 0 ∴ x = 3, 3/4 II. 20y² -  23y + 6 = 0 20y² -  8y - 15 y + 6 = 0 4 y(5 y – 2) – 3(5 y - 2) = 0 (4 y - 3) (5 y – 2) = 0  ∴ y = 2/5 ,3/4 Hence, x ≥ y
I. 49y2 + 35y + 6 = 0
II. 12x2 + 17 x + 6 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
I. √(17x) + √51 = 0  Â
II. √(4y) + 3 = 0
I. 4 x ² - 4 x + 1 = 0                              Â
II. 4 y ² + 4 y  + 1 = 0
...I. 64x2 - 64x + 15 Â = 0 Â Â Â Â
II. 21y2 - 13y + 2Â =0
I. 2y2 - 15y + 18 = 0
II. 2x2 + 9x - 18 = 0
I. 3q² -29q +18 = 0
II. 9p² - 4 = 0
I: 3x² - 18x + 24 = 0
II: 5y² + 10y - 15 = 0
(i) 2x² + 14x - 16 = 0
(ii) y² – y – 12 = 0
The following question contains two equations as I and II.You have to solve both equations and determine the relationship between them.
I). 2a²...
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