Question
I. 4x² -  15x + 9 = 0 II. 20y² -  23y + 6 =
0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 4x² -  15x + 9 = 0 4x² -  12x - 3 x + 9 = 0 4 x(x – 3) – 3 (x – 3) = 0 (4 x – 3) (x – 3) = 0 ∴ x = 3, 3/4 II. 20y² -  23y + 6 = 0 20y² -  8y - 15 y + 6 = 0 4 y(5 y – 2) – 3(5 y - 2) = 0 (4 y - 3) (5 y – 2) = 0  ∴ y = 2/5 ,3/4 Hence, x ≥ y
I. x2 – 36 = 0
II. y2 - 7y + 6 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. 2x<...
I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 5x + 6 = 0
Equation 2: y² - 7y + 12 = 0
I.√(3x-17)+ x=15
II. Â y+ Â 135/y=24Â
Find the roots of the equation 6p² – 5p – 6 = 0.
If α, β are the roots of the equation x² – px + q = 0, then the value of α2+β2+2αβ isÂ
...I. 63x² + 146x + 80 = 0
II. 42y² + 109y + 70 = 0
I. 3x2 – 16x + 21 = 0
II. y2 – 13y + 42 = 0
I. √(74x-250 )– x=15
II. √(3y²-37y+18)+ 2y=18
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