Question
I. 4x2 + 3√7 x-7 =0 II. 7y2
+ 4√7 y-5=0 In each of these questions, two equations numbered I and II are given. You have to solve both the equation and mark the appropriate option – give answerSolution
I. 4x^2+ 3√7 x-7 =0 4x^2+ 4√7 x-√7 x-7 =0 4x(x+ √7)- √7 (x+ √7)= 0 (x+ √7) (4x- √7)= 0 x= -√7 , √7/4 Or x= (-7√7)/7 , √7/4 II. 7y^2+ 4√7 y-5=0 7y^2+ 5√7 y- √7-5=0 √7 y (√7 y+5)- 1(√7 y+5)= 0 (√7 y+5)(√7 y-1)= 0 y= (-5)/√7 , 1/√7 Or y= (-5√7)/7 , √7/7 Hence, No relation can be established between x and y
I. x2 - 4x – 21 = 0
II. y2 + 12y + 20 = 0
I. 2x2 - 5x - 33 =0
II. 2y2 + 5y - 25 = 0
I. 2x² + 15 x - 27 = 0
II. 3 y² + 25 y - 18 = 0
I. 3x2 = 2x2 + 9x – 20
II. 3y2 = 75
I. x2-2x- √5x+2√5 = 0
II. y2-√3 y- √2 y+ √6 = 0
...Solve the equation:- x² − 9x + 20 = 0, What is the larger root?
I. x2 - 17x + 70 = 0
II. y2 - 11y + 28 = 0
I. 15b2 + 26b + 8 = 0
II. 20a2 + 7a - 6 = 0
What is the average salary of 10 officers , if a clerk’s salary is Rs. 15,000?
Statement I: The total salary of 10 officers and 5 clerk is Rs....
I. 12y2 + 11y – 15 = 0
II. 8x2 – 6x – 5 = 0