Question
I. 4x2 + 3√7 x-7 =0 II. 7y2
+ 4√7 y-5=0 In each of these questions, two equations numbered I and II are given. You have to solve both the equation and mark the appropriate option – give answerSolution
I. 4x^2+ 3√7 x-7 =0 4x^2+ 4√7 x-√7 x-7 =0 4x(x+ √7)- √7 (x+ √7)= 0 (x+ √7) (4x- √7)= 0 x= -√7 , √7/4 Or x= (-7√7)/7 , √7/4 II. 7y^2+ 4√7 y-5=0 7y^2+ 5√7 y- √7-5=0 √7 y (√7 y+5)- 1(√7 y+5)= 0 (√7 y+5)(√7 y-1)= 0 y= (-5)/√7 , 1/√7 Or y= (-5√7)/7 , √7/7 Hence, No relation can be established between x and y
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