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    Question

    I. 6x2 - 41x+13=0 II. 2y2

    - 19y+42=0 In each of these questions, two equations numbered I and II are given. You have to solve both the equation and mark the appropriate option – give answer
    A If, x>y Correct Answer Incorrect Answer
    B If, x≥y Correct Answer Incorrect Answer
    C If, x Correct Answer Incorrect Answer
    D If, x≤y Correct Answer Incorrect Answer
    E If, x=y or relationship between x and y cannot be established. Correct Answer Incorrect Answer

    Solution

    I. 6x^2- 41x+13=0 6x^2- 39x-2x+13=0 3x(2x-13)- 1 (2x-13)= 0 (2x-13)(3x-1)= 0 x= 13/2 ,1/3 II. 2y^2- 19y+42=0 2y^2- 12y-7y+42=0 2y (y-6)- 7 (y-6)= 0 (y-6)(2y-7)= 0 y=6 ,7/2 Hence, no relation between x and y can be established

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