Question
I. x= Β β(20+ β(20+ β(20+
β(20β¦β¦β¦β¦β¦.β)) ) )Β II. y= β(5β(5β(5β(5β¦β¦β¦.β)) ) )Β In each of these questions, two equations numbered I and II are given. You have to solve both the equation and mark the appropriate option β give answerSolution
I. x= Β β(20+ β(20+ β(20+ β(20β¦β¦β¦β¦β¦.β)) ) )Β x= β(20+x)Β By squaring both sides, x^2=20+xΒ x^2- x-20=0Β x^2- 5x+4x-20=0Β x(x-5)+4(x-5)= 0Β x= Β 5,-4Β II. y= β(5β(5β(5β(5β¦β¦β¦.β)) ) )Β y= β5yΒ By squaring both sides, y^2=5yΒ y=5Β Hence, xβ€y
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