Question
I. x= √(20+ √(20+ √(20+
√(20…………….∞)) ) ) II. y= √(5√(5√(5√(5……….∞)) ) ) In each of these questions, two equations numbered I and II are given. You have to solve both the equation and mark the appropriate option – give answerSolution
I. x= √(20+ √(20+ √(20+ √(20…………….∞)) ) ) x= √(20+x) By squaring both sides, x^2=20+x x^2- x-20=0 x^2- 5x+4x-20=0 x(x-5)+4(x-5)= 0 x= 5,-4 II. y= √(5√(5√(5√(5……….∞)) ) ) y= √5y By squaring both sides, y^2=5y y=5 Hence, x≤y
- If sec 2P = sin² 60⁰ + sec 60⁰ - cos² 30⁰, then determine the value of (√3tan P + cot² P)
Find the value of the given trigonometric expression:
(sin 25°cos 65° + cos²25°) × sin 30° + (cos 60°tan 45°) × sec 60°
...If cos² x + sin x = 5/4, then find the value of 'sin x'.
If sin A - cos A = 3/7, then find value of sinA + cos B, where A is an acute angle.
The Value of (sin38˚)/(cos52˚)+ (cos12˚)/(sin78˚)- 4cos²60˚ is
- Find the value of sin²40° + sin²50° + cos²60° + cos²30°.
Find the value of the given expression.
2 × (sec 60° – sin 30°)
If tan θ + cot θ = 5, find the value of tan²θ + cot²θ.
Evaluate the following:
sin 25° × cos 65° + sin 65° × cos 25°
If cos 2A = 1, then find cos A
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