I. x=  √(20+ √(20+ √(20+ √(20…………….∞)) ) )Â
II. y= √(5√(5√(5√(5……….∞)) ) )Â
I. x=  √(20+ √(20+ √(20+ √(20…………….∞)) ) ) x= √(20+x) By squaring both sides, x^2=20+x x^2- x-20=0 x^2- 5x+4x-20=0 x(x-5)+4(x-5)= 0 x=  5,-4 II. y= √(5√(5√(5√(5……….∞)) ) ) y= √5y By squaring both sides, y^2=5y y=5 Hence, x≤y
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