Question
I. x2 β 39x + 360 = 0 II.
y2 β 36y + 315 = 0Solution
From I: x2 β 39x + 360 = 0 Or, x2 β 15x β 24x + 360 = 0 Or, x Γ (x β 15) β 24 Γ (x β 15) = 0 Or, (x β 15) Γ (x β 24) = 0 So, x = 15 or, x = 24 From II: y2 β 36y + 315 = 0 Or, y2 β 15y β 21y + 315 = 0 Or, y Γ (y β 15) β 21 Γ (y β 15) = 0 Or, (y β 15) Γ (y β 21) = 0 So, y = 15 or y = 21 So, the relationship cannot be established. Hence, option c.
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