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    Question

    I. x2 тАУ 39x + 360 = 0 II.

    y2 тАУ 36y + 315 = 0
    A x > y Correct Answer Incorrect Answer
    B x < y Correct Answer Incorrect Answer
    C x = y or the relationship cannot be established Correct Answer Incorrect Answer
    D x тЙе y Correct Answer Incorrect Answer
    E x тЙд y Correct Answer Incorrect Answer

    Solution

    From I: x2 тАУ 39x + 360 = 0 Or, x2 тАУ 15x тАУ 24x + 360 = 0 Or, x ├Ч (x тАУ 15) тАУ 24 ├Ч (x тАУ 15) = 0 Or, (x тАУ 15) ├Ч (x тАУ 24) = 0 So, x = 15 or, x = 24 From II: y2 тАУ 36y + 315 = 0 Or, y2 тАУ 15y тАУ 21y + 315 = 0 Or, y ├Ч (y тАУ 15) тАУ 21 ├Ч (y тАУ 15) = 0 Or, (y тАУ 15) ├Ч (y тАУ 21) = 0 So, y = 15 or y = 21 So, the relationship cannot be established. Hence, option c.

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