Question
I. x2 – 39x + 360 = 0 II.
y2 – 36y + 315 = 0Solution
From I: x2 – 39x + 360 = 0 Or, x2 – 15x – 24x + 360 = 0 Or, x × (x – 15) – 24 × (x – 15) = 0 Or, (x – 15) × (x – 24) = 0 So, x = 15 or, x = 24 From II: y2 – 36y + 315 = 0 Or, y2 – 15y – 21y + 315 = 0 Or, y × (y – 15) – 21 × (y – 15) = 0 Or, (y – 15) × (y – 21) = 0 So, y = 15 or y = 21 
So, the relationship cannot be established. Hence, option c.
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