Question
I. 3x2 + 3x - 60 = 0
II. 2y2 - 7y + 5 = 0Solution
I. 3x2 + 3x - 60 = 0 Pairs = 15, -12 And now dividing by a and by changing the sign we get, x = -5, 4 II. 2y2 - 7y + 5 = 0 Pairs = -2, -5 And now dividing by a and by changing the sign we get, y = 1, 2.5 From these comparisons, we can see that x1(4) is greater than both y₁ (2.5) and y2 (1), while x2(-5) is less than both y1 (2.5) and y2(1). Since one root of x is greater than both roots of y and the other root of x is less than both roots of y, we cannot establish a consistent relationship between x and y. ∴ The relationship between x and y cannot be established.
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