Question
In the question, two equations I and II are given. You
have to solve both the equations to establish the correct relation between 'p' and 'q' and choose the correct option. I. 8p2 + (40+√2)p + 5√2 = 0 II. 9q2 - (27+13√2)q + 39√2 = 0Solution
ATQ, I. 8p2 + (40+√2)p + 5√2 = 0 8p2 + 40p + √2p + 5√2 = 0 8p (p + 5) + √2 (p + 5) = 0 p = -5, -√2/8 II. 9q2 - (27+13√2)q + 39√2 = 0 9q2 – 27q - 13√2q + 39√2 = 0 9q (q- 3) - 13√2 (q - 3) = 0 q = 3, 13√2/9 Hence, p < q
I. x2 + (9x/2) + (7/2) = - (3/2)
II. y2 + 16y + 63 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x2 + 6√7x - 315 = 0    Â
E...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 17x² - 78x + 61 = 0
Equation 2: 19y² - 89y + 70 ...
l. p2Â - 3p - 54 = 0
II. q2Â - 19q + 90 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 54x + 704 = 0
Equation 2: y² - 44y + 448 = 0
I. Â 2(x+2)+ 2(-x)=5
II. Â (1/(y+1)+ 1/(y+5))=(1/(y+2)+ Â 1/(y+4))
Equation 1: x² - 180x + 8100 = 0
Equation 2: y² - 170y + 7225 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 20x + 96 = 0
Equation 2: y² - 18y + 72 = 0
I. 5x + 2y = 31
II. 3x + 7y = 36
The roots of x² − (k+3)x + (3k − 1) = 0 are real and distinct, and the larger root exceeds the smaller by 5. Find k.
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