Question
In the question, two equations I and II are given. You
have to solve both the equations to establish the correct relation between 'p' and 'q' and choose the correct option. I. p2 - 11√2p + 60 = 0     II. q2 - 10√3q + 72 = 0Solution
ATQ, I. p2 - 11√2p + 60 = 0      Pairs = -5√2, -6√2 And now dividing by 1 and by changing the sign we get, p = 5√2, 6√2 p = 7, 8.4 (√2 = 1.4) II. q2 - 10√3q + 72 = 0 Pairs = -6√3, -4√3 And now dividing by 1 and by changing the sign we get, q = 6√3, 4√3 q = 10.2, 6.8 (√3 = 1.7) Hence, the relation between p and q cannot be established.
If a and b are the roots of x² + x – 2 = 0, then the quadratic equation in x whose roots are 1/a + 1/b and ab is
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 45x + 450 = 0
Equation 2: y² - 48y + 540 = 0�...
I. 14p² + 9p - 8 = 0
II. 4q² - 19q + 12 = 0
I. 35x² + 83x + 36 = 0
II. 42y² + 53y + 15 = 0
I. x² - (16)2 = 0
II. 2y - 14 = 0
I. 5q = 7p + 21
II. 11q + 4p + 109 = 0
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
I. 2p2 - 3p – 2 = 0 II. 2q2 - 11q + 15 = 0
Solve the quadratic equation:
5x² − 13x + 6 = 0
I. 2y² - 35y + 132 = 0
II. 2x² - 31x + 110 = 0
