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    Question

    I.  2p² - 11p + 12 = 0 II. 2q² - 17q + 36 =

    0 In each of these questions two equations numbered I and II are given. You have to solve both the equations and give answer, if – 
    A p = q or relationship between p and q can’t be established. Correct Answer Incorrect Answer
    B p > q Correct Answer Incorrect Answer
    C p < q Correct Answer Incorrect Answer
    D p ≥ q Correct Answer Incorrect Answer
    E p ≤ q Correct Answer Incorrect Answer

    Solution

    I.  2p² - 11p + 12 = 0 2p² - 8 p  - 3p + 12 = 0 2p(2 p – 4) - 3 (p – 4) = 0 (2p – 3) (p – 4) = 0 p = 4 , 3/2 II. 2q² - 17q + 36 = 0 2q² - 8q  - 9q + 36 = 0 2q(q - 4)  - 9( q - 4) = 0 (2q - 9) (q - 4) = 0 q = 4  ,9/2 Hence p≤ q

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