In the question, two equations I and II are given. You

Solution

ATQ, I. 2p² + 41p + 210= 0 Pairs are 21, 20 Values after changing sign = - 21, - 20 and after dividing by 2, Final values of p = -10.5, - 10. II. 2q² - 45q + 253= 0 Pairs are -22, -23 Values after changing sign = 22, 23 and after dividing by 2,  Final values of q =  11, 11.5 Hence, p < q Alternate Method: The sign of both roots of x are negative and the sign of both roots of y are positive so no need to find the exact value of roots as negative is always lesser than positive value Hence p < q.