Question
I. x2 β 13x + 36 = 0 II.
3y2 β 29y + 18 = 0 In each question two equations numbered (I) and (II) are given. You should solve both the equations and mark appropriate answer.Solution
I. x2 β 13x + 36 = 0 => x2 β 9x β 4x + 36 = 0 => x (x β 9) β 4 (x β 9) = 0 => x = 9, 4 II. 3y2 β 29y + 18 = 0 => 3y2 β 27y β 2y + 18 = 0 => 3y (y β 9) β 2(y β 9) = 0 => y = 9, 2/3 Hence, the relation between x and y cannot be established. Alternate Method: if signs of quadratic equation is - ve and +ve respectively then the roots of equation will be +ve and +ve. So, roots of first equation = x = 9, 4 So, roots of second equation = y = 9, 2/3 After comparing we can conclude that no relationship can be establish in x and y.
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