New RBI Grade B 2025 Notification will come Soon! Enroll Here

    Question

    In each question two equations numbered (I) and (II) are given. You should solve both the equations and mark appropriate answer.

    I. x2 – 13x + 36 = 0 II.

    3y2 – 29y + 18 = 0
    A if x > y Correct Answer Incorrect Answer
    B if x ≥ y Correct Answer Incorrect Answer
    C if x < y Correct Answer Incorrect Answer
    D if x ≤ y Correct Answer Incorrect Answer
    E if x = y or the relation between x and y cannot be established Correct Answer Incorrect Answer

    Solution

    I. x2 – 13x + 36 = 0 => x2 – 9x – 4x + 36 = 0 => x (x – 9) – 4 (x – 9) = 0 => x = 9, 4 II. 3y2 – 29y + 18 = 0 => 3y2 – 27y – 2y + 18 = 0 => 3y (y – 9) – 2(y – 9) = 0 => y = 9, 2/3 Hence, the relation between x and y cannot be established. Alternate Method: if signs of quadratic equation is - ve and +ve respectively then the roots of equation will be +ve and +ve. So, roots of first equation = x = 9, 4 So, roots of second equation = y = 9, 2/3 After comparing we can conclude that no relationship can be establish in x and y.

    Practice Next

    Relevant for Exams: