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    Question

    I. 2x2 тАУ 5x - 12 = 0 II.

    y2 тАУ 11y + 30 = 0 In each question two equations numbered (I) and (II) are given. You should solve both the equations and mark appropriate answer.
    A if x > y Correct Answer Incorrect Answer
    B if x тЙе y Correct Answer Incorrect Answer
    C if x < y Correct Answer Incorrect Answer
    D if x тЙд y Correct Answer Incorrect Answer
    E if x = y or the relation between x and y cannot be established Correct Answer Incorrect Answer

    Solution

    I. 2x2 тАУ 5x - 12 = 0 => 2x2 тАУ 8x + 3x - 12 = 0 => 2x (x тАУ 4) + 3 (x тАУ 4) = 0 => x = -3/2, 4 II. y2 тАУ 11y + 30 = 0 => y2 тАУ 6y тАУ 5y + 30 = 0 => y (y тАУ 6) тАУ 5(y тАУ 6) = 0 => y = 6, 5 Hence, x < y

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