Question
I. 2x2 – 5x – 63 = 0 II.
2y2 – 7y – 72 = 0Solution
I. 2x2 – 5x – 63 = 0 2x2 + 9x – 14x – 63 = 0 x (2 x + 9) – 7 (2 x + 9) = 0 (x – 7) (2 x + 9) = 0 x = 7, -9/2 II. 2y2 – 7y – 72 = 0 2y2 – 16 y + 9y – 72 = 0 2 y(y – 8) + 9 (y – 8) = 0 (2 y + 9) (y – 8) = 0 y = 8, -9/2 Hence, relationship cannot be established between x and y
I. Â 3y2Â + 13y - 16 = 0
II. 3x2 – 13x + 14 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 31x² - 170x + 216 = 0
Equation 2: 22y² - 132y + ...
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
I. 2y2Â + 11y + 15 = 0
II. 3x2Â + 4x - 4= 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. 5x² = 19x – 12
II. 5y² + 11y = 12
I. x2 – 13x + 40 = 0
II. 2y2 – 15y + 13 = 0Â
I. x² + 3x – 154 = 0
II. y² + 5y – 126 = 0
I. x² + 11x + 24 = 0
II. y² + 17y + 72 = 0
I. 4p² + 17p + 15 = 0
II. 3q² + 19q + 28 = 0