Question
I. 40 x² - 93 x + 54 = 0 II. 30 y² - 61
y + 30 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 40 x² - 93 x + 54 = 0 40 x² - 48 x - 45 x + 54 = 0 8 x(5 x – 6) – 9(5 x – 6) = 0 (8 x – 9) (5 x – 6) = 0 x = 9/8,6/5 II. 30 y² - 61 y + 30 = 0 30 y² - 36 y - 25 y + 30 = 0 6 y(5 y – 6) – 5(5 y – 6) = 0 (6 y – 5) (5 y – 6) = 0 y = 5/6, 6/5 Hence, relationship cannot be established between x and y
I. x2 – 36 = 0
II. y2 - 7y + 6 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. 2x<...
I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 5x + 6 = 0
Equation 2: y² - 7y + 12 = 0
I.√(3x-17)+ x=15
II. Â y+ Â 135/y=24Â
Find the roots of the equation 6p² – 5p – 6 = 0.
If α, β are the roots of the equation x² – px + q = 0, then the value of α2+β2+2αβ isÂ
...I. 63x² + 146x + 80 = 0
II. 42y² + 109y + 70 = 0
I. 3x2 – 16x + 21 = 0
II. y2 – 13y + 42 = 0
I. √(74x-250 )– x=15
II. √(3y²-37y+18)+ 2y=18
Relevant for Exams:
