Question
Aβ and βBβ together can complete a work in 20 days
while βAβ takes 30 days to complete the same work alone. If βCβ is 25% more efficient than βBβ, then find the time taken by βCβ alone to complete the whole work.Solution
Let the total work = 60 units Efficiency of (A + B) = 60/20 = 3 units/day Efficiency of βAβ = 60/30 = 2 unit/day Therefore, efficiency of βBβ = 3 β 2 = 1 units/day Efficiency of βCβ = 1.25 Γ 1 = 1.25 units/day Required time taken = 60/1.25 = 48 days
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