Question
A’ and ‘B’ together can complete a work in 25 days
while ‘A’ takes 30 days to complete the same work alone. If ‘C’ is 20% more efficient than ‘B’, then find the time taken by ‘C’ alone to complete the whole work.Solution
Let the total work = 150 units Efficiency of (A + B) = 150/25 = 6 units/day Efficiency of ‘A’ = 150/30 = 5 unit/day Therefore, efficiency of ‘B’ = 6 – 5 = 1 units/day Efficiency of ‘C’ = 1.2 × 1 = 1.20 units/day Required time taken = 150/1.20 = 125 days
More Time and work Questions
?% of 1200.22 + 319.82 = 3.99 × 295.64
?% of (140.31 ÷ 19.97 × 80.011) = 139.98
30.05% of 149.97 + ? X 8.88 = (39.95 + 12.012 - 13.0322)2
41.97 × 5.12 ÷ 2.99 + 49.89 = ?× 1.99
(8000)1/3 × 10.11 × 8.97 ÷ 18.32 = ? + 25.022
?% of 309.99 = 40.01% of 249.99 + 295.98% of 49.99
(? + 11.86) X 14.89 = 19.89% of 2399.89
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
? = 499.87 – 24.95 × 14.04 + (20.15)²
(32.25 × 14.98) + 31.76% of 1499.89 = ? × 3.67
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