Question
A’ and ‘B’ together can complete a work in 25 days
while ‘A’ takes 30 days to complete the same work alone. If ‘C’ is 20% more efficient than ‘B’, then find the time taken by ‘C’ alone to complete the whole work.Solution
Let the total work = 150 units Efficiency of (A + B) = 150/25 = 6 units/day Efficiency of ‘A’ = 150/30 = 5 unit/day Therefore, efficiency of ‘B’ = 6 – 5 = 1 units/day Efficiency of ‘C’ = 1.2 × 1 = 1.20 units/day Required time taken = 150/1.20 = 125 days
More Time and work Questions
(13)2 - 3127 ÷ 59 = ? x 4
Solve the following equation.
143 + 14.3 + 1.43 + 0.143 + 0.0143 =?
Simplify the following expressions and choose the correct option.
(45% of 640) ÷ 8 + (3/4 of 96) = ?
55.55% of 30000 – 1111 = ? × 1111
Find the simplified value of the following expression:
[{12 + (13 × 4 ÷ 2 ÷ 2) × 5 – 8} + 13 of 8]
24 × √? + 4008 ÷ 24 = 40% of 200 + 327
∛21952 × 44 = ? × 14
26 2 – 13% of 400 + (529 ÷ 23 2 ) = ? 2
- What will come in place of (?) in the given expression.
[45 + (36 ÷ 6)] × 2 – 10 = ? 25.6% of 250 + √? = 119
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