Question
Aβ and βBβ together can complete a work in 25 days
while βAβ takes 30 days to complete the same work alone. If βCβ is 20% more efficient than βBβ, then find the time taken by βCβ alone to complete the whole work.Solution
Let the total work = 150 units Efficiency of (A + B) = 150/25 = 6 units/day Efficiency of βAβ = 150/30 = 5 unit/day Therefore, efficiency of βBβ = 6 β 5 = 1 units/day Efficiency of βCβ = 1.2 Γ 1 = 1.20 units/day Required time taken = 150/1.20 = 125 days
The average age of A, B and C is 40 years, while the average age of B, A and D is 30 years. If the ratio of the age of C and D is 5:3, respectively, the...
The ratio of age of βBβ after 6 years from now and age of βCβ 4 years ago from now is 7:4, respectively. The present age of βCβ is 40% of th...
Currently, the average age of individuals 'A' and 'B' is 27 years. If the present ages of 'B' and 'C' maintain a ratio of 10:11, determine the age of 'C...
Sum of the present ages of A, B, C and D is 54 years. After 4 years ratio of their ages is 5:4:3:2. What is C’s present age?
Present age of βCβ is 20% more than that of βDβ. 3 years ago, βCβ was 1.4 times as old as βDβ. Find the present age of βDβ.
...The sum of ages of 4 children born at the intervals of 2 years each is 36 years. Find out the age of the youngest child.
- The ratio of the ages of a teacher and a student is 5:2, respectively. If the difference between their ages is 18 years, then find the age of the student.
βAβ is 7 years younger than βBβ and 6 years elder than βCβ. If the present age of βBβ and βDβ is 35 years and 24 years, respectively...
The average ages of A, B and C is 20% more than the average ages of A and B. 10years hence from now, the ratio of the ages of A and C will be 3:5, respe...
- The current age of βXβ is 36 years which is 20% more than the age of βYβ. The average age of βYβ and βZβ is 45 years. The ratio of present ...