Question
Aβ and βBβ together can complete a work in 22 days
while βAβ takes 33 days to complete the same work alone. If βCβ is 20% more efficient than βBβ, then find the time taken by βCβ alone to complete the whole work.Solution
Let the total work = 66 units Efficiency of (A + B) = 66/22 = 3 units/day Efficiency of βAβ = 66/33 = 2 unit/day Therefore, efficiency of βBβ = 3 β 2 = 1 units/day Efficiency of βCβ = 1.2 Γ 1 = 1.20 units/day Required time taken = 66/1.20 = 55 days
112, 119, 133, 154, 180, 217
Find the wrong number in the given number series.
127, 296, 585, 908, 1475, 2316
132, 192, 238, 266, 284, 292
11, 12, 20, 58, 234, 1168
45, 125, 214, 312, 420, 535
90, 110, 132, 156, 182, 215
Find the wrong number in the given number series.
233, 206, 183, 152, 125, 98
40, 56, 85, 129, 190, 268
- Find the wrong number in the given number series.
8, 19, 12, 23, 16, 36 8, 17, 35, 71, 143, 287