Question
Arjun and Sameer can complete a job in 20 days and 25
days respectively. When Arjun, Sameer, and Nikhil work together, they finish it in . If they receive a combined reward of Rs. (5x + 1000), then Nikhil’s share is how much percent more than Sameer’s?Solution
ATQ; Let total work = 100 units Efficiency of 'Arjun' = 100/20=5 units/day Efficiency of 'Sameer' = 100/25=4 units/day Combined efficiency = 100÷(20/3)=15 units/day Efficiency of 'Nikhil' = 15−(5+4)=6 units/day Ratio of Arjun : Sameer : Nikhil = 5 : 4 : 6 So, shares = Rs. 5a, Rs. 4a, Rs. 6a respectively Required percent = [(6a - 4a)/4a] × 100 = 50%
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8, 12, 23, 40, 66, 103
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78, 66, 51, 39, 20, 12
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