Question
'B' and 'N' can collectively finish a task in 88 days,
and 'N' and 'S' together can complete the same work in 66 days. If 'B' and 'S' work together, they can finish the job in 72 days. Determine the ratio of the efficiencies of 'B', 'N', and 'S', respectively.Solution
ATQ, Let, the total work be 792 units (LCM of 88, 66 and 72) Amount of work done by 'B' and 'N' together in one day = (792/88) = 9 units Amount of work done by 'N' and 'S' together in one day = (792/66) = 12 units Amount of work done by 'B' and 'S' together in one day = (792/72) = 11 units Amount of work done by 'B', 'N' and 'S' together in one day = {(9 + 12 + 11) /2} = 16 units Amount of work done by 'B' alone in one day = 16 - 12 = 4 units Amount of work done by 'N' alone in one day = 16 - 11 = 5 units Amount of work done by 'S' alone in one day = 16 - 9 = 7 units So, the desired ratio = 4:5:7
500, 250, 750, 375, 1125, 562.5, ?
What will come in place of the question mark (?) in the following series?
520, 519, 511, ?, 420, 295
What will come in place of the question mark (?) in the following series?
72, 108, 172, ?, 416, 612
In each of the following series, one term is missing. Find the missing term.
5, 13, 29, 61, 125, ?
What will come in place of the question mark (?) in the following series?
15, 26, 39, 56, ?, 98
What will come in place of the question mark (?) in the following series?
120, 130, ?, 140, 100, 150
107    157    194    ?     237    247
...14, 86, 150, ?, 254, 294
98, 134, 198, ?, 442, 638
In each of the following number series, one term is missing. Find the missing term.
1, 4, 9, 16, 25, ?
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