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Area of the circle = πr2 616 = 22/7 × r2 r2 = 196 r = 14 cm (Since, radius cannot be negative) Radius of the circle = 14 cm Diameter of the circle = 2r = 28 cm Length of the rectangle = (28/7) × 11 = 44 cm Breadth of the rectangle = (28/7) × 7 = 40 cm Perimeter of the rectangle = 2 × (44 + 40) = 168 cm Circumference of the circle = 2 × (22/7) × 14 = 88 cm Required difference = 168 – 88 = 80 cm
I. 3p² - 11p + 10 = 0
II. 2q² + 13q + 21 = 0
(i) 2x² + 14x - 16 = 0
(ii) y² – y – 12 = 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x² - 8x + 15 = 0 ...
I. 2(x+2)+ 2(-x)=5
II. (1/(y+1)+ 1/(y+5))=(1/(y+2)+ 1/(y+4))
I. x² + 3x – 154 = 0
II. y² + 5y – 126 = 0
I. 35x² - 46x – 16 = 0
II. 35y² - 116y + 96 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 11x² - 93x + 88 = 0
Equation 2: 13y² + 118y + 93 = 0
I. x² - (16)2 = 0
II. 2y - 14 = 0
Let 's' represent the sum of the highest root of equations I and III, and 'r' denote the product of the lowest root of equation I and the highest root o...
I. y² + y – 56 = 0
II. 2x² + 11 x – 40 = 0
