Question
βAβ and βBβ can do a piece of work in 20 days
and 40 days, respectively. If they started the work together and worked on it for 6 days, then find the time taken by βBβ alone to complete the remaining work.Solution
Let total amount of work be 40 unitsΒ Efficiency of βAβ = 40/20 = 2 units/day Efficiency of βBβ = 40/40 = 1 units/day Amount of work done by βAβ and βBβ together in 6 days = (2 + 1) Γ 6 = 18 units Time taken by B to complete remaining work = (40 β 18)/1 = 22 days
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