Question
‘A’ and ‘B’ can do a piece of work in 20 days
and 40 days, respectively. If they started the work together and worked on it for 6 days, then find the time taken by ‘B’ alone to complete the remaining work.Solution
Let total amount of work be 40 units Efficiency of ‘A’ = 40/20 = 2 units/day Efficiency of ‘B’ = 40/40 = 1 units/day Amount of work done by ‘A’ and ‘B’ together in 6 days = (2 + 1) × 6 = 18 units Time taken by B to complete remaining work = (40 – 18)/1 = 22 days
More Time and work Questions
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
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