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    Question

    A can complete 25% of work in five days. And this takes

    four days more than B to complete the whole work. They started the work together but after X days A left and C was 50% as efficient as a joined B and completed the whole work with him. If the total work got completed in 2X days, then find the value of X.
    A 3 Correct Answer Incorrect Answer
    B 4 Correct Answer Incorrect Answer
    C 6 Correct Answer Incorrect Answer
    D 5 Correct Answer Incorrect Answer
    E 7 Correct Answer Incorrect Answer

    Solution

    Time taken by A to complete the whole work alone = 20 days. time taken by B To complete the whole work alone = 20-4 = 16 days Let total work = 80 unit (LCM of 20 and 16) Efficiency of A= 80/20 = 4 units/day Efficiency of B = 80/ 16 = 5 Units/day. Efficiency of C = 0.5*4 =┬а 2 units/ day Also B&C together worked for= X days. (4+5)*x+(5+2)*x = 80 16x=80 X=5 Therefore efficiency of D,= (X + 11)= 16 units / day Required. Time taken. = 80/16 = 5 days

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