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Time taken by A to complete the whole work alone = 20 days. time taken by B To complete the whole work alone = 20-4 = 16 days Let total work = 80 unit (LCM of 20 and 16) Efficiency of A= 80/20 = 4 units/day Efficiency of B = 80/ 16 = 5 Units/day. Efficiency of C = 0.5*4 = 2 units/ day Also B&C together worked for= X days. (4+5)*x+(5+2)*x = 80 16x=80 X=5 Therefore efficiency of D,= (X + 11)= 16 units / day Required. Time taken. = 80/16 = 5 days
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