Question
A can complete 25% of work in five days. And this takes
four days more than B to complete the whole work. They started the work together but after X days A left and C was 50% as efficient as a joined B and completed the whole work with him. If the total work got completed in 2X days, then find the value of X.Solution
Time taken by A to complete the whole work alone = 20 days. time taken by B To complete the whole work alone = 20-4 = 16 days Let total work = 80 unit (LCM of 20 and 16) Efficiency of A= 80/20 = 4 units/day Efficiency of B = 80/ 16 = 5 Units/day. Efficiency of C = 0.5*4 =Â 2 units/ day Also B&C together worked for= X days. (4+5)*x+(5+2)*x = 80 16x=80 X=5 Therefore efficiency of D,= (X + 11)= 16 units / day Required. Time taken. = 80/16 = 5 days
What approximate value should replace the question mark?
12.45% of 640.20 − 60% of 2500 = ? − 9000.10
`[(7.99)^2 - (13.001)^2 + (4.01)^3]^2=` ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What value should come in place of question mark (?) in the following question. (You need not to calcualte the exact value)
?/647 = 226/ ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
A, B & C have Rs.1550 together. If they divide the money in the ratio 1:3:1 respectively. Find the difference of amount received by B and C.
What approximate value should come in the place of (?) in the following questions?
∛(92.8 + √1025) * ? = 16.06% of 750
√1024.21 × √624.89 ÷ 4.98 + 11.99 × 4.01 = ?
√784 × 3 + (713.99 ÷ 6.98) = ?% of 619.99
11.11% of (123.45 + 234.56) + 10.01³ - (5.05 of 7.07) = ? of (88.88 - 33.33)
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