ЁЯУв Too many exams? DonтАЩt know which one suits you best? Book Your Free Expert ЁЯСЙ call Now!

    Question

    Meena and Mohit, alone can complete a work in 12 days

    and 18 days, respectively. They started the work together and left after 4 days such that the remaining work is completed by Mehul alone in 6 days. If the total wage fixed for completing the work is Rs. 540, then find the share received by Mehul.
    A Rs. 180 Correct Answer Incorrect Answer
    B Rs. 200 Correct Answer Incorrect Answer
    C Rs. 120 Correct Answer Incorrect Answer
    D Rs. 240 Correct Answer Incorrect Answer
    E Rs. 150 Correct Answer Incorrect Answer

    Solution

    Let total work = 36 units {LCM of 12 and 18} So, efficiency of тАШMeenaтАЩ = (36/12) = 3 units/day Efficiency of тАШMohitтАЩ = (36/18) = 2 units/day Amount of work done by Meena in 4 days = 3 ├Ч 4 = 12 units Amount of work done by Mohit in 4 days = 2 ├Ч 4 = 8 units Amount of work done by Mehul = 36 тАУ (12 + 8) = 16 units Ratio of amount of work done by Meena, Mohit and Mehul = (12 : 8 : 16) = (3 : 2 : 4) Required wages of Mehul = {4/(3 + 2 + 4)} ├Ч 540 = Rs. 240

    Practice Next
    More Time and work Questions
    ask-question