Question
Meena and Mohit, alone can complete a work in 12 days
and 18 days, respectively. They started the work together and left after 4 days such that the remaining work is completed by Mehul alone in 6 days. If the total wage fixed for completing the work is Rs. 540, then find the share received by Mehul.Solution
Let total work = 36 units {LCM of 12 and 18} So, efficiency of ‘Meena’ = (36/12) = 3 units/day Efficiency of ‘Mohit’ = (36/18) = 2 units/day Amount of work done by Meena in 4 days = 3 × 4 = 12 units Amount of work done by Mohit in 4 days = 2 × 4 = 8 units Amount of work done by Mehul = 36 – (12 + 8) = 16 units Ratio of amount of work done by Meena, Mohit and Mehul = (12 : 8 : 16) = (3 : 2 : 4) Required wages of Mehul = {4/(3 + 2 + 4)} × 540 = Rs. 240
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