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ATQ; Let the total task be = 36 {LCM(18, 12)} Efficiency of ‘Aman’ = (36/12) = 3 units/day Efficiency of ‘Bhanu’ = (36/18) = 2 units/day task done by ‘Aman’ in 4 days = 3 × 4 = 12 units task done by ‘Aman’ and ‘Bhanu’ together in 3 days = 5 × 3 = 15 units Remaining task = 36 – 12 – 15 = 9 units Time taken by ‘Bhanu’ to complete the remaining task = 9/2 = 4.5 days
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