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Let total work = 60 units (LCM of 12 and 20)
Efficiency of 'P' = (60/12) = 5 units/day
Efficiency of 'Q' = (60/20) = 3 units/day
Amount of work completed by 'P' and 'Q' together in 6 days = 6 X (5 + 3) = 48 units
Remaining work = 60 - 48 = 12 units
Time taken by 'P' to complete the remaining work = (12/5) = 2.4 days
Required time taken = 6 + 2.4 = 8.4 days
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