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P can do a work in 15 days. Q can do a work in 25 days. Let P left after x days. Q worked for (x+5) days. ∴ 1/15 × x + 1/25 (x+5) = 1 x/15 + x/25 + 1/5 = 1 (5x+3x)/75 = 4/5 8x/75 = 4/5 x = 15/2 days Alternate method: Let total work = LCM(15, 25) = 75 So P’s 1 day work = 5 & Q’s 1 day work =3 So Q’s 5 days work in last = 3×5 = 15 So remaining work = 75 – 15 = 60 So this 60 units of work is completed by both in = 60/(5+3) = 60/8 =7.5 days
Statements: A % B & G % B; B # L & J; J @ K # S
Conclusions:
I. L @ K
II. A % K
III. S @ B
...In this question, the relation between various elements is shown in the statement. After the statement, two conclusions are given, select a suitable op...
Statements: Q $ Z % C # T @ H
Conclusions:
I. Z # H
II. Q © T
III. H % Z
In Which of the following expressions does the expression ‘ H ≥ D ’ definitely hold true?
Statements: D < O = Q > U < I ≤ R; K ≥ O = I; R > H ≥ G
Conclusions:
I. R > O
II. K > U
III. H ≥ Q
Statements: Z % Y; X # W; U % V; W & V; Y @ X
Conclusions:
I. U @ X �...
Statements: 1 > 2 ≥ 3 = 4 < 5 ≤ 6; 7 ≥ 8 = 9 < 4 = 10 ≥ 11
Conclusions:
I. 2 ≥ 10
II. 3 < 7
III. 6 > 11
Statements: P ≥ Q ≥ R = S, Q ≥ T > U ≥ V
Conclusion:
I. P ≥ V
II. P > V
Statement: L ≥ M ≤ R = S; M > N ≥ P
Conclusions: I. P ≤ M II. L > N
Which of the following symbols should be placed in the blank spaces respectively (in the same order from left to right) in order to complete the given e...