P and Q can separately finish the work in 15 days and 25 days respectively. They worked together and P left the work, so Q complete the remaining work in 5 days. After how many days P left the work?
P can do a work in 15 days. Q can do a work in 25 days. Let P left after x days. Q worked for (x+5) days. ∴ 1/15 × x + 1/25 (x+5) = 1 x/15 + x/25 + 1/5 = 1 (5x+3x)/75 = 4/5 8x/75 = 4/5 x = 15/2 days Alternate method: Let total work = LCM(15, 25) = 75 So P’s 1 day work = 5 & Q’s 1 day work =3 So Q’s 5 days work in last = 3×5 = 15 So remaining work = 75 – 15 = 60 So this 60 units of work is completed by both in = 60/(5+3) = 60/8 =7.5 days
I. 8x² - 78x + 169 = 0
II. 20y² - 117y + 169 = 0
I. 3x² - 5x + 2 = 0
II. 6y² - 19y + 14 =0
I. 2(x+2)+ 2(-x)=5
II. (1/(y+1)+ 1/(y+5))=(1/(y+2)+ 1/(y+4))
I. 195x² - 46x - 21 = 0
II. 209y² + 7y - 12 = 0
I. 15y2+ 26y + 8 = 0
II. 20x2+ 7x – 6 = 0
I. 96y² - 76y – 77 = 0
II. 6x² - 19x + 15 = 0
I. 6 y² + 11 y – 7= 0
II. 21 x² + 5 x – 6 = 0
I. 3y² - 20y + 25 = 0
II. 3x² - 8x + 5 = 0
I. 2x² + 11 x + 15 = 0
II. 2y² - 19 y + 44 = 0
I. 4x² - 21x + 20 = 0
II. 8y² - 22y + 15 = 0
