Question
A' can finish a job in 24 days, while 'B' is 25% less
efficient than 'A.' If they take turns working, beginning with 'A,' how many days will it take for them to complete 87.5% of the task?Solution
ATQ, Time taken by βBβ to complete the work = 24/0.75 = 32 days Let the total work = 96 units Efficiency of βAβ = 96/24 = 4 units/day Efficiency of βBβ = 96/32 = 3 units/day Work to be done = 0.875 Γ 96 = 84 units Work completed by βAβ and βBβ in 2 days = (4 + 3) = 7 units Therefore, to complete 84 units of work time required = 2 Γ (84/7) = 24 days
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