Question
A can complete a piece of work in 80 days, B takes 20% more
time than A to complete the same work while C takes 25% more time than B to complete the whole work. Find the time taken by all of them together to complete the whole work.Solution
Time taken by B to complete the whole work = 1.2 × 80 = 96 days
Time taken by C to complete the whole work = 1.25 × 96 = 120 days
Total work (let) = 480 units (LCM of 80, 96 and 120)
Efficiency of A, B and C is 6 units/day, 5 units/day and 4 units/day respectively
Desired Time = 480/15 = 32 days
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