Question
βAβ and βBβ can do a piece of work in 20 days
and 32 days, respectively. If they started the work together and worked on it for 5 days, then find the time taken by βBβ alone to complete the remaining work.Solution
Let total amount of work be 160 unitsΒ Efficiency of βAβ = 160/20 = 8 units/day Efficiency of βBβ = 160/32 = 5 units/day Amount of work done by βAβ and βBβ together in 5 days = (8 + 5) Γ 5 = 65 units Time taken by B to complete remaining work = (160 β 65)/5 = 19 days
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